某公司需招聘一名員工,對應聘者*、乙、*從筆試、面試、體能三個方面進行量化考核,*、乙、*各項得分如下表:筆試...
問題詳情:
某公司需招聘一名員工,對應聘者*、乙、*從筆試、面試、體能三個方面進行量化考核,*、乙、*各項得分如下表:
筆試 | 面試 | 體能 | |
* | 83 | 79 | 90 |
乙 | 85 | 80 | 75 |
* | 80 | 90 | 73 |
(1)根據三項得分的平均分,從高到低確定三名應聘者的排名順序.
(2)該公司規定:筆試,面試、體能得分分別不得低於80分,80分,70分,並按60%,30%,10%的比例計入總分,根據規定,請你説明誰將被錄用.
【回答】
解:(1) =(83+79+90)÷3=84,
=(85+80+75)÷3=80,
=(80+90+73)÷3=81.············································································ 3分
從高到低確定三名應聘者的排名順序為:*,*,乙;··································· 4分
(2)∵該公司規定:筆試,面試、體能得分分別不得低於80分,80分,70分,
∴*淘汰,···································································································· 5分
乙成績=85×60%+80×30%+75×10%=82.5,······················································· 7分
*成績=80×60%+90×30%+73×10%=82.3,····················································· 9分
∴乙將被錄取. ························································································· 10分
知識點:數據的波動程度
題型:解答題