有關3483kJ的精選大全

已知:①Zn(s)+O2(g)=ZnO(s)ΔH=-348.3kJ·mol-1       ②2Ag(s)+O...
問題詳情:已知:①Zn(s)+O2(g)=ZnO(s)ΔH=-348.3kJ·mol-1       ②2Ag(s)+O2(g)=Ag2O(s)ΔH=-31.0kJ·mol-1   則Zn與Ag2O反應生成ZnO和Ag的熱化學方程式為A.2Zn(s)+2Ag2O(s)===2ZnO(s)+4Ag(s)ΔH=-634.6kJ·mol-1B.Zn+Ag2O==...
已知:①Zn(s)+1/2O2(g)=ZnO(s) ΔH=-348.3kJ·mol-1       ②2Ag(...
問題詳情:已知:①Zn(s)+1/2O2(g)=ZnO(s) ΔH=-348.3kJ·mol-1       ②2Ag(s)+1/2O2(g)=Ag2O(s) ΔH=-31.0kJ·mol-1   則Zn與Ag2O反應生成ZnO和Ag的熱化學方程式為A.Zn(s)+Ag2O(s)=ZnO(s)+2Ag(s) ΔH=+317.3kJ·mol-1B.Zn...
已知:①Zn(s)+O2(g)=ZnO(s)ΔH=-348.3kJ·mol-1             ②2A...
問題詳情:已知:①Zn(s)+O2(g)=ZnO(s)ΔH=-348.3kJ·mol-1             ②2Ag(s)+O2(g)=Ag2O(s)ΔH=-31.0kJ·mol-1   則Zn與Ag2O反應生成ZnO和Ag的熱化學方程式為   A.Zn(s)+Ag2O(s)===ZnO(s)+2Ag(s)ΔH=+317.3kJ·...
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