有關980kJmol的精選大全

常温下,已知:CH4(g)+2O2(g)=CO2(g)+2H2O(1) ∆H=-980kJ/mol 2H2(g...
問題詳情:常温下,已知:CH4(g)+2O2(g)=CO2(g)+2H2O(1) ∆H=-980kJ/mol 2H2(g)+O2(g)=2H2O(1) △H=-560kJ/mol現有CH4和H2組成的混合氣體共0.4mol,使其在O2中完全燃燒,恢復至常温共放出252kJ的熱量,則CH4與H2的物質的量...
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